9th maths Guess Paper for CBSE Exam


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Obtaining and Utilization Food Class 7 Science Solved question (Basic Science Questions answers)

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A. Answer these questions 1. Name the three life process help living being to procure energy from food? Answer: Three life processes that help living organisms to procure energy from food are: (i) Digestion (Nutrition) (ii) Respiration (iii) Transportation 2. What are Autotrophs? Name an organism other than other than green plant that is an autotroph. Answer: Autotrophs are organisms that can prepare their own food. Chlamydomonas is a type of green algae which is an example of an autotroph, other than green plants. Cyanobacteria are also an example of autotroph. 3. Name three type of heterotrophic nutrition Answer: Three types of heterotrophic nutrition are: (i) Saprophytic nutrition (ii) Parasitic nutrition (iii) Holozoic nutrition 4. What are enzymes? Answer: Enzymes are chemical substances that act as biological catalysts and are important for carrying out biochemical processes, such as digestion, in our body
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Plants fiber and fabric solution Cordova Learning Science class07

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A Tick the correct options: 1. Which of the following is not a natural fibre? (a) cotton (b) rayon √ (c) silk (d) wool 2. Lohi is the breed of (a) cow (b) silk moth (c) sheep √ (d) buffalo 4. Sheep are sheared in season (a) summer √ (b) spring (c) autumn Ö (d) winter 3. How many weeks are required for the eggs of silk moth to hatch? See book (a) one (b) two √ (c) three (d) four 6. Which of the following silk is produced when raw silk is twisted? (a) spun (b) coloured (c) thrown √ (d) mooga 5. What do we call the silky covering spun by the silkworm for its protection? (a) moth (b) larvae (c) pupa (d) cocoon√ B. Fill in the blanks: 1. Alpaca is generally f
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HEREDITY AND EVOLUTION SOLVED EXERCISES QUESTIONS [Biology Term-2 CHAPTER - 13]

Q.1. What is heredity? Ans:- Heredity refers to the transmission of characters or traits from the parents to their offspring. Q.2. Name the plant on which Mendel performed his experiments? Ans:- Garden Pea ( Pisum sativum .) Q.3. Define variation? Ans:-Variation refers to the differences in the characters or traits about the individuals of a species. Q.4. Define a gene? Ans:- Gene is a small segment of DNA on a chromosome occupying specific position in which is a hereditary determinant or unit of a biological function. Q.5.Write the expanded form of DNA? Ans:- DNA - Deoxyribonucleic Acid. Q.6. What are the components of chromosome? Ans:- Each chromosome is double or replicated and consists of two thread like structures called chromatids attached to each other at centromere. .Each chromatid has a number of dense areas arranged linearly which are known as chromomeres. They represent the areas of active genes. .Internally each chromosome has two spirally coiled
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10 class acids salt and base Exam oriented Board Questions

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Q. How is NH4OH used as a laboratory reagent? Answer:  NH4OH is used to detect cations in their salt solutions by precipitating their hydroxides whose colour and solubility in excess NH4OH, identifies them. Q. Though NaHSO 4  solution releases H +  ions, why is it not called an acid? Answer:  NaHSO 4  solution is not called an acid because an acid should release only H +  ions as positive ions and not any other positive ions. But NaHSO 4  is solution releases H +  ions as well as Na +  ions also as positive ion. Q. How would you distinguish between baking powder and washing soda by heating? Answer: Sodium hydrogencarbonate on heating gives CO2 gas which will turn lime water milky whereas no such gas is obtained from sodium carbonate. 2NaHCO3 ---Heat → Na2CO3 + H2O + CO2      Na2CO3.10H2O -Heat → Na2CO3 + 10H2O Q. Why aqueous solution of sodium carbonate is basic in nature? Answer: Sodium bicarbonate is an amphoteric compound. Aqueous solutions are mildly alkaline due
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Derivation of Lens and mirror formula X Reflection and Refraction of light

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MIRROR FORMULA The relation between object distance(u), image distance(v) and the focal length (f) of the mirror is known as MIRROR FORMULA. Consider a concave mirror MM' (of small aperture). An object AB of height h is placed on the left of the mirror beyond its center of curvature so that the image formed is real, inverted and diminished in size(height = h'). Here : Object distance = PB = -u Image distance = PB'= -v Focal length = PF = -f Radius of curvature = PC = -R As shown in Figure, Δ ABP ∼ Δ A'B'P. ∴ A'B'/AB = PB'/PB ∴ A'B'/AB = (-v)/(-u) ∴ A'B'/AB = v/u.............(I) Similarly, as shown in the figure, Δ ABC ∼ Δ A'B'C. ∴ A'B'/AB = CB'/CB ∴ A'B'/AB = (PC-PB')/(PB-PC)........[as CB'=(PC-PB') and CB=(PB-PC)] ∴ A'B'/AB = [-R - (-v)]/[-u - (-R)] ∴ A'B'/AB = (-R + v)/(-u + R)........(II) By (I) & (II), v/u = (-R + v)/(-u + R) ∴ -
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