9th maths Guess Paper for CBSE Exam


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VI (6th) Fun with Magnets MCQ’s

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CBSE - Class 6 - Science Chapter :Fun with  Magnets Multiple choice Questions (1) When a magnet is suspended freely it always aligns itself in --------  direction? a) North        b) N-S          c) N-W         d) N-E (2) ---------- is the only natural magnet. a) Magnetite         b) Ebonite      c) Cobalt      d) Nickel (3) Which of the following cannot be used to make a magnet? a) Cobalt              b) Iron                      c) Ebonite     d) Steel (4) Which of the following is not a non-magnetic substance? a) Glass    ...
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X Solved:The Human Eye and the Colorful World :Chapter – 11

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Chapter – 11 The Human Eye and the  Colorful  World Q 1. What is meant by power of accommodation of the eye? Ans. The ability of the eye lens to adjust its focal length, so as to clearly focus rays coming from distant as well a near objects on the retina, is called the power of accommodation of the eye. Q2. A person with a myopic eye cannot see objects beyond 1.2 m distinctly. What should be the type of the corrective lens used to restore proper vision? Ans. A person with a myopic eye should use a concave lens of focal length 1.2 m so as to restore proper vision. Q 3. What is the far point and near point of the human eye with normal vision? Ans. For a human eye with normal vision the far point is at infinity and the near point is at 25 cm from the eye. Q 4. A student has difficulty reading the blackboard while sitting in the last row. What could be the defect the child is suffering from? How can it be corrected? Ans. The student is suffering from myopia...
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CBSE:10th Math :Chapter Triangles : Solved Concept builder theorems

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If a line divides any two sides of a triangles proportionally then the line is parallel to the third side Statement:   If a line divides any two sides of a triangles proportionally (in same ratio), then the line is parallel to the third side. Proof:   We are given ABC   AD / BD = AE / CE We have to prove: DE is parallel to BC Let DE's not parallel to BC then an another line DE' is parallel to BC. Now AD / BD = AE / CE [Given] And AD / BD = AE' / CE' [ Thales Theorem ] Therefore AE / CE = AE' / CE' i.e. AE / CE + 1 = AE' / CE' + 1 i.e. AE + CE / CE = AE' + CE' / CE'   i.e. CE = CE' But this is not possible until E and E' is coincident. Thus, our assumption is wrong and DE is parallel to BC. X Triangles :Criteria for Similarity of Triangles Solved:    10th math Triangles Thales theorem   10th math Converse of Thales theorem   Angle bisector theorem   10th math SAS similarity of triangle 10th SSS similarit...
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Class9 Biology chapter Cell the Fundamental unit of life :Assignment solved

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1. What is plasma membrane? What are their functions? Ans: Plasma membrane also called as cell membrane, is the outer covering of a cell that separates the cell contents (protoplasm) from the surrounding medium. It is made up of proteins and lipids. It gives form (shape and size) to the cell It maintains the individuality of the cell (i.e. seperates cells) It keeps the cell contents in place 2. What are cell organelles ? Ans: The certain specific living parts of a cell with a definite function are celled Cell organelles. All cell are found to have same organelles and together these constitute to the basic unit of life. 3. What is cellulose and its functions? Ans: Cellulose is the main component of a plant cell wall. It is responsible for giving structural shape to the cell and also to protect the protoplasm. 4.  What is a Prokaryotic cell? Give an Example. Ans: The cells that do not hav...
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Derivation of Lens and mirror formula X Reflection and Refraction of light

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MIRROR FORMULA The relation between object distance(u), image distance(v) and the focal length (f) of the mirror is known as MIRROR FORMULA. Consider a concave mirror MM' (of small aperture). An object AB of height h is placed on the left of the mirror beyond its center of curvature so that the image formed is real, inverted and diminished in size(height = h'). Here : Object distance = PB = -u Image distance = PB'= -v Focal length = PF = -f Radius of curvature = PC = -R As shown in Figure, Δ ABP ∼ Δ A'B'P. ∴ A'B'/AB = PB'/PB ∴ A'B'/AB = (-v)/(-u) ∴ A'B'/AB = v/u.............(I) Similarly, as shown in the figure, Δ ABC ∼ Δ A'B'C. ∴ A'B'/AB = CB'/CB ∴ A'B'/AB = (PC-PB')/(PB-PC)........[as CB'=(PC-PB') and CB=(PB-PC)] ∴ A'B'/AB = [-R - (-v)]/[-u - (-R)] ∴ A'B'/AB = (-R + v)/(-u + R)........(II) By (I) & (II), v/u = (-R + v)/(-u + R) ∴ -...
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